A) \[\phi =\pi ,3\pi ,5\pi ,.................\]
B) \[\phi =(2\pi +1)\pi \,n=1,2,3,..............\]
C) \[=\frac{2\pi }{\lambda }\times \]
D) \[\Rightarrow \]
Correct Answer: C
Solution :
The orbital velocity of a satellite close to earth is given by \[F=-\frac{{{k}_{1}}{{k}_{2}}}{{{k}_{1}}+{{k}_{2}}}y\] .....(1). where \[\frac{{{k}_{1}}{{k}_{2}}}{{{k}_{1}}+{{k}_{2}}}\], is radius of earth and g is acceleration due to gravity. The escape velocity of a body thrown from earths surface is \[n=\frac{1}{2\pi }\sqrt{\frac{{{k}_{1}}{{k}_{2}}}{({{k}_{1}}+{{k}_{2}})m}}\] ???.(2) Thus, \[\frac{1}{k}=\frac{1}{{{k}_{1}}}+\frac{1}{{{k}_{2}}}\] \[k=\frac{{{k}_{1}}{{k}_{2}}}{{{k}_{1}}+{{k}_{2}}}\] \[n=\frac{1}{2\pi }\sqrt{\frac{k}{m}}\]
You need to login to perform this action.
You will be redirected in
3 sec
