A) \[{{C}_{4}}H{{O}_{4}}\]
B) \[{{C}_{5}}{{H}_{10}}{{O}_{5}}\]
C) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]
D) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}.\]
Correct Answer: D
Solution :
Empirical formula of compound is \[C{{H}_{2}}O\]Empirical mass \[=12+2+16=30\] Molecular weight of compound = 180 As, \[n=\frac{molecular\,mass}{empirical\,mass}=\frac{180}{30}=6\] Therefore, Molecular formula of compound is \[{{(C{{H}_{2}}O)}_{6}}={{C}_{6}}{{H}_{12}}{{O}_{6}}\]
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