AIIMS AIIMS Solved Paper-1999

  • question_answer
    The equivalent weight of phosphoric acid \[({{H}_{3}}P{{O}_{4}})\] in the reaction: \[NaOH+{{H}_{3}}P{{O}_{4}}\to Na{{H}_{2}}P{{O}_{4}}+{{H}_{2}}O\] is                

    A)  25                         

    B)         49                       

    C)                         59                         

    D)         98.                     

    Correct Answer: D

    Solution :

    The given reaction is: \[NaOH+{{H}_{3}}P{{O}_{4}}\to Na{{H}_{2}}P{{O}_{4}}+{{H}_{2}}O\] Molecular mass ofH3P04 is 98. As there is only one electron change involved therefore, equivalent 98 weight of \[{{H}_{3}}P{{O}_{4}}\] in this reaction is, \[\frac{98}{1}=98\]


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