A) \[{{O}^{2-}}>O>{{F}^{-}}>F\]
B) \[{{F}^{-}}>{{O}^{2-}}>F>O\]
C) \[{{O}^{2-}}>{{F}^{-}}>F>O\]
D) \[{{O}^{2-}}>{{F}^{-}}>O>F\]
Correct Answer: D
Solution :
We know that anion is always larger than the corresponding atom therefore \[{{F}^{-}}>F\] and \[{{O}^{2-}}>O.\] Also, in a period, size of the atom decreases from left to right due to greater force of attraction exerted correct order is: \[{{o}^{2-}}>{{F}^{-}}>O>F\]
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