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AIIMS AIIMS Solved Paper-1999

  • question_answer
    If a cyclist moving with a speed of 4.9 m/s on a level road can take a sharp circular turn of radius 4 m, then coefficient of friction between the cycle tyres and road is

    A) 0.51    

    B)                                        0.41                       

    C)        0.71                       

    D)        0.61.

    Correct Answer: D

    Solution :

                    We know that while a cyclist moving with a speed v takes a sharp turn on a circular track of radius r, the coefficient of friction is given by        \[\mu =\tan \theta =\frac{{{v}^{2}}}{rg}\] Here \[v=4.9\text{ }m/s\] \[r=4\text{ }m\]                                                 and \[g=9.8\text{ }m/{{s}^{2}}\] \[\therefore \]  \[\mu =\frac{4.9\times 4.9}{4\times 9.8}=0.61\]


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