A) \[6.25\times {{10}^{23}}\]
B) \[6.25\times {{10}^{21}}\]
C) \[6.25\times {{10}^{19}}\]
D) \[6.25\times {{10}^{18}}.\]
Correct Answer: D
Solution :
We know that \[1\,e=1.6\times {{10}^{-19}}C\] \[\Rightarrow \] \[1C=\frac{1}{1.6\times {{10}^{-19}}}=6.25\times {{10}^{18}}\]electrons
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