Directions for Question: The questions consist of two statements each, printed as assertion and reason. While answering these questions you are required to choose any one of the following four responses:
Assertion: Reaction of cone. \[{{H}_{2}}S{{O}_{4}}\] on \[NaBr\] and \[Nal\] does not give \[HBr\] and \[HI\]. Reason: \[HBr\]and \[HI\]are oxidised by cone. \[{{H}_{2}}S{{O}_{4}}\] to \[B{{r}_{2}}\] and \[{{I}_{2}}\].A) If both A and R are true, and R is a correct explanation of the A.
B) If both A and R are true, but R is not a correct explanation of the A.
C) If A is true, but R is false.
D) If both A and R are false.
Correct Answer: A
Solution :
\[{{H}_{2}}S{{O}_{4}}\] when react with \[NaBr\] and \[NaI\], give out \[B{{r}_{2}}\] and \[{{I}_{2}}\] as concentrated \[{{H}_{2}}S{{O}_{4}}\] is a strong oxidising agent.
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