A) \[\frac{Mg}{k}\]
B) \[\frac{Mg}{k}\left( 1-\frac{LA\sigma }{M} \right)\]
C) \[\frac{Mg}{k}\left( 1-\frac{LA\sigma }{2M} \right)\]
D) \[\frac{Mg}{k}\left( 1+\frac{LA\sigma }{M} \right)\]
Correct Answer: C
Solution :
\[\left( K{{x}_{0}}+\frac{LA}{2}\sigma g \right)=mg\] \[\therefore \] \[{{x}_{0}}=\frac{Mg}{k}\left( 1-\frac{LA\alpha }{2M} \right)\]
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