JEE Main & Advanced AIEEE Solved Paper-2012

  • question_answer
    The length of the diameter of the circle which touches the x-axis at the point (1, 0) and passes through the point (2, 3) is :   AIEEE  Solved  Paper-2012

    A) \[\frac{10}{3}\]                                    

    B) \[\frac{3}{5}\]

    C) \[\frac{6}{5}\]                                      

    D) \[\frac{5}{3}\]

    Correct Answer: A

    Solution :

                 Now \[{{h}^{2}}={{(1-2)}^{2}}+{{(h-3)}^{2}}\] \[0=1-6h+9\] \[6h=10\] \[h=\frac{5}{3}\] Now diameter is \[2h=\frac{10}{3}\]


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