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JEE Main & Advanced AIEEE Solved Paper-2012

  • question_answer
    For a first order reaction (A) \[\to \] products the concentration of A changes from 0.1 M to 0.025Min 40minutes. The rate of reaction when the concentration of A is 0.01 M is :   AIEEE  Solved  Paper-2012

    A) \[1.73\times {{10}^{-5}}\] M/min                

    B) \[3.47\times {{10}^{-4}}\] M/min

    C) \[3.47\times {{10}^{-5}}\] M/min                

    D) \[1.73\times {{10}^{-4}}\] M/min

    Correct Answer: B

    Solution :

                 \[K=\frac{1}{40}In\frac{0.1}{0.025}=\frac{1}{40}In4\] \[R=K{{[A]}^{1}}=\frac{1}{40}In4.(0.1)=\frac{2In2}{40}(0.1)=3.47\times {{10}^{-4}}\]


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