AIEEE Solved Paper-2012
A) 15.4%
B) 9.1%
C) 10.5%
D) 12.5%
Correct Answer: A
Solution :
\[\eta =\frac{{{p}_{0}}{{v}_{0}}}{\frac{f}{2}({{p}_{0}}{{v}_{0}})+\frac{f}{2}(2{{p}_{0}}){{v}_{0}}+2{{p}_{0}}{{v}_{0}}}=\frac{1}{\frac{3}{2}+3+2}\] \[=\frac{200}{13}=15.4%\]
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