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JEE Main & Advanced AIEEE Solved Paper-2011

  • question_answer
    Trichloroacetaldehyde was subject to Cannizzaro's reaction by using NaOH. The mixture of the products contains sodium trichloroacetate and another compound. The other compound is :   AIEEE  Solved  Paper-2011

    A) Chloroform

    B) 2, 2, 2-Trichloroethanol

    C) Trichloromethanol

    D) 2, 2, 2-Trichloropropanol

    Correct Answer: B

    Solution :

                   \[Cl-\overset{\begin{smallmatrix}  Cl \\  | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix}  | \\  Cl \end{smallmatrix}}{\mathop{C}}\,}}\,-CHO\xrightarrow[Cannizaros\,\,reaction]{NaOH}Cl-\overset{\begin{smallmatrix}  Cl \\  | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix}  | \\  Cl \end{smallmatrix}}{\mathop{C}}\,}}\,-COONa+\]                                                    \[Cl-\overset{\begin{smallmatrix}  Cl \\  | \end{smallmatrix}}{\mathop{\underset{{{|}_{\begin{smallmatrix}   \\  Cl \end{smallmatrix}}}^{2}}{\mathop{C}}\,}}\,-\underset{1}{\mathop{C{{H}_{2}}}}\,-OH\]                                    2,2,2- trichloroethanol


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