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JEE Main & Advanced AIEEE Solved Paper-2010

  • question_answer
      If\[\alpha \]and\[\beta \]are the roots of the equation \[{{x}^{2}}x\]\[+1=0,\] then\[{{\alpha }^{2009}}+{{\beta }^{2009}}=\]       AIEEE  Solved  Paper-2010

    A) -2         

    B) -1                         

    C) 1                             

    D) 2  

    Correct Answer: C

    Solution :

    Here roots of\[{{x}^{2}}x+1=0\]are\[\omega \]and\[{{\omega }^{2}}\]. \[{{(\text{ }\omega )}^{2009}}+{{({{\omega }^{2}})}^{2009}}={{(\omega )}^{2007}}\times {{(\omega )}^{2}}+\] \[{{({{\omega }^{2}})}^{2007}}\times {{({{\omega }^{2}})}^{2}}({{\omega }^{2}}+\omega )=1.\]


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