• question_answer One ticket is selected at random from 50 tickets numbered 00, 01, 02, ... , 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals     AIEEE  Solved  Paper-2009 A) 1/14B)                        1/7                        C)                                        5/14      D)        1/50

Solution :

A = Events that sum of the digits on selected ticket is 8 $=\{08,\text{ }17,\text{ }26,\text{ }35,\text{ }44\}$ $n(A)=5$ Event that product of digits is zero $=\{00,01,02,03,04,05,06,07,08,09,10,20,$ $30,40\}$ $\Rightarrow$ $n(B)=14$ $P\left( \frac{A}{B} \right)=\frac{5}{14}$

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