JEE Main & Advanced AIEEE Solved Paper-2009

  • question_answer One ticket is selected at random from 50 tickets numbered 00, 01, 02, ... , 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals     AIEEE  Solved  Paper-2009

    A) 1/14

    B)                        1/7                        

    C)                                        5/14      

    D)        1/50

    Correct Answer: A

    Solution :

    A = Events that sum of the digits on selected ticket is 8 \[=\{08,\text{ }17,\text{ }26,\text{ }35,\text{ }44\}\] \[n(A)=5\] Event that product of digits is zero \[=\{00,01,02,03,04,05,06,07,08,09,10,20,\] \[30,40\}\] \[\Rightarrow \] \[n(B)=14\] \[P\left( \frac{A}{B} \right)=\frac{5}{14}\]

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