JEE Main & Advanced AIEEE Solved Paper-2008

  • question_answer
      The coordination number and the oxidation state of the element 'E' in the complex \[[E{{(en)}_{2}}({{C}_{2}}{{O}_{4}})]N{{O}_{2}}\] (where (en) is ethylene diamine) are, respectively,       AIEEE  Solved  Paper-2007

    A) 4 and 3

    B) 6 and 3

    C) 6 and 2

    D) 4 and 2

    Correct Answer: B

    Solution :

    (en) and oxalate ion are both bidentate ligands. Co?ordination number of E in the complex \[=(2\times 2)+(1\times 2)=6\]. Oxidation state of E in the complex \[[x+(-2)=+1]=+3\].


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