A) \[6.8.\,{{\,}^{7}}{{C}_{4}}\]
B) \[7.{{\,}^{6}}{{C}_{4}}.{{\,}^{8}}{{C}_{4}}\]
C) \[8.{{\,}^{6}}{{C}_{4}}.{{\,}^{7}}{{C}_{4}}\]
D) \[6.7.{{\,}^{8}}{{C}_{4}}\]
Correct Answer: B
Solution :
1M, 4I?s and 2P?s can be arranged by \[\frac{7!}{4!\,\,\,2!}\] and in the 8 gaps 4 S can arranged with \[^{8}{{C}_{4}}\] ways, so total ways are \[7.{{\,}^{6}}{{C}_{4}}.\,{{\,}^{8}}{{C}_{4}}\]
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