A) \[{{y}^{2}}=x\]
B) \[y=|\text{ }x|\]
C) \[\frac{2}{3}\]
D) zero
Correct Answer: D
Solution :
On introduction and removal and again on introduction, the capacity and potential remain same. So, net work done by the system in this process \[x=(2\times {{10}^{-2}})\cos \pi t\]
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