question_answer

In the chemical reaction, \[{{V}_{0}}+g/2+f\] \[\sqrt{2}{{I}_{AC}}={{I}_{EF}}\]the compounds (A) and (B) are respectively       AIEEE  Solved  Paper-2007

A)  \[{{I}_{AD}}=4{{I}_{EF}}\]and \[{{I}_{AC}}={{I}_{EF}}\]

B)         \[{{I}_{AC}}=\sqrt{2}{{I}_{EF}}\]and\[x={{x}_{0}}\cos (\omega t-\pi /4)\]

C)         \[a=A\text{ }cos(\omega t+\delta ),\]and \[A={{x}_{0}},\text{ }\delta =-\pi /4\]

D)         \[A={{x}_{0}}{{\omega }^{2}},\text{ }\delta =\pi /4\]and\[A={{x}_{0}}{{\omega }^{2}},\text{ }\delta =-\pi /4\]

Correct Answer: D

Solution :

\[\frac{{{\mu }_{0}}}{2\pi d}(I_{1}^{2}+I_{2}^{2})\] \[C{{H}_{3}}C{{l}_{2}}+KOH\xrightarrow{\,}:CC{{l}_{2}}\,+\underset{[B]}{\mathop{KCl}}\,+{{H}_{2}}O\]