A) 416
B) \[2.40\times {{10}^{-3}}\]
C) \[9.8\times {{10}^{-2}}\]
D) \[4.9\times {{10}^{-2}}\]
Correct Answer: A
Solution :
Equilibrium constant for the reaction \[S{{O}_{2}}(g)+\frac{1}{2}{{O}_{2}}S{{O}_{3}}(g)\] \[{{K}_{c}}=\frac{1}{4.9\times {{10}^{-2}}}\] and for\[2S{{O}_{2}}+{{O}_{2}}2S{{O}_{3}}(g)\] \[{{K}_{c}}={{\left( \frac{1}{4.9\times {{10}^{-2}}} \right)}^{2}}=\frac{{{10}^{4}}}{{{(4.9)}^{2}}}=416.49\]
You need to login to perform this action.
You will be redirected in
3 sec
