JEE Main & Advanced AIEEE Solved Paper-2006

  • question_answer
    How many moles of magnesium phosphate, \[M{{g}_{3}}{{(P{{O}_{4}})}_{2}}\]will contain 0.25 mole of oxygen atoms?     AIEEE  Solved  Paper-2006

    A) 0.02                       

    B)        \[3.125\times {{10}^{-2}}\]         

    C)        \[1.25\times {{10}^{-2}}\]      

    D)        \[2.5\times {{10}^{-2}}\]

    Correct Answer: B

    Solution :

    \[M{{g}_{3}}{{(P{{O}_{4}})}_{2}}=1\,mole\] 8 moles of 0-atom are contained by 1 mole \[M{{g}_{3}}{{(P{{O}_{4}})}_{2}}\] Hence, 0.25 moles of 0 atom\[=\frac{1}{8}\times 0.25\] \[=3.125\times {{10}^{-2}}\]


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