JEE Main & Advanced AIEEE Solved Paper-2006

  • question_answer
    Density of a 2.05 M solution of acetic acid in water is\[1.02\text{ }g/mL\]. The molality of the solution is     AIEEE  Solved  Paper-2006

    A) \[1.14\text{ }mol\text{ }k{{g}^{-1}}\]     

    B) \[3.28\text{ }mol\text{ }k{{g}^{-1}}\]

    C)        \[2.28\text{ }mol\text{ }k{{g}^{-1}}\]                     

    D) \[0.44\text{ }mol\text{ }k{{g}^{-1}}\]

    Correct Answer: C

    Solution :

    Molality\[(m)=\frac{M}{1000d-M{{M}_{1}}}\times 100\] \[M=\]Molarity.\[{{M}_{1}}=\]Molecular mass \[d=Density=\frac{2.05}{(1000\times 1.02)-(2.05\times 60)}\times 1000\]             \[=2.28\,mol\,k{{g}^{-1}}\]


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