A) increasing\[bp-bp\]repulsion
B) increasing p-orbital character in\[s{{p}^{3}}\]
C) decreasing \[lp-bp\] repulsion
D) decreasing electronegativity
Correct Answer: D
Solution :
\[N{{H}_{3}}>P{{H}_{3}}>As{{H}_{3}}>Sb{{H}_{3}}\] As the electronegativity of central atom increases, bonded electron polarise towards central atom more, so, repulsion increases and bond angle increases.
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