question_answer

The relation between time t and distance\[x\]is \[t=a{{x}^{2}}+bx,\]where a and b are constants. The acceleration is       AIEEE  Solved  Paper-2005          

A) \[-2ab{{v}^{2}}\]             

B)        \[2b{{v}^{3}}\] 

C)        \[-2a{{v}^{3}}\]                

D)        \[2a{{v}^{2}}\]

Correct Answer: C

Solution :

Given, Differentiating w.r.t. t Again differentiating w.r.t. t   or