An observer moves towards a stationary source of sound, with a velocity one-fifth of the velocity of sound. What is the percentage increase in the apparent frequency?
AIEEE Solved Paper-2005
A)Zero
B) 0.5%
C) 5%
D) 20%
Correct Answer:
D
Solution :
Given, \[{{v}_{o}}=\frac{v}{5}\] When observer moves towards the stationary source, then Hence, percentage increase \[=\left( \frac{64}{320}\times 100 \right)%=20%\]