question_answer

Two simple harmonic motions are represented by the equations \[{{y}_{1}}=0.1\sin \left( 100\pi t+\frac{\pi }{3} \right)\]and\[{{y}_{2}}=0.1\,\cos \pi t.\] The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is     AIEEE  Solved  Paper-2005

A) \[\frac{-\pi }{6}\]      

B)                        \[\frac{\pi }{3}\]                              

C)        \[\frac{-\pi }{3}\]                             

D)        \[\frac{\pi }{6}\]

Correct Answer: A

Solution :

  Given,   or            or            and     \[{{y}_{2}}=0.1\,\cos \,\pi t\]            Hence, phase difference