JEE Main & Advanced AIEEE Solved Paper-2005

  • question_answer
    The figure shows a system of two concentric spheres of radii\[{{r}_{1}},{{r}_{2}}\]and kept at temperatures \[{{T}_{1}},{{T}_{2}},\]respectively. The radial rate of flow of heat in a substance between the two concentric spheres, is proportional to     AIEEE  Solved  Paper-2005

    A) \[\frac{({{r}_{2}}-{{r}_{1}})}{({{r}_{1}}{{r}_{2}})}\]            

    B)        \[\ln \left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)\]      

    C)        \[\frac{{{r}_{1}}{{r}_{2}}}{({{r}_{2}}-{{r}_{1}})}\]

    D)        \[({{r}_{2}}-{{r}_{1}})\]

    Correct Answer: C

    Solution :

    To measure the radial rate of heat flow, we have to go for integration technique as here the area of the surface through which heat will flow is not constant. Let us consider an element (spherical shell) of thickness ox and radius x as shown in figure. Let us first find the equivalent thermal resistance between inner and outer sphere. The thermal resistance of shell (from\[R=\frac{l}{KA},\]where K is thermal conductivity) The total thermal resistance, Now, rate of heat flow


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