JEE Main & Advanced AIEEE Solved Paper-2005

  • question_answer
    Two points A and B move from rest along a straight line with constant acceleration f and f?, respectively. If A takes m second more than B and describes n unit more than B in acquiring the same speed, then     AIEEE  Solved  Paper-2005

    A) \[(f'-f)n=\frac{1}{2}ff'{{m}^{2}}\]

    B)        \[\frac{1}{2}(f+f')m=ff'{{n}^{2}}\]

    C) \[(f+f'){{m}^{2}}=ff'n\]

    D) \[(f+f'){{m}^{2}}=ff'n\]

    Correct Answer: A

    Solution :

    If u is initial velocity of any particle and a is a acceleration, then where, v is a speed of particle after t seconds. We have,                                     ... (i)                                               ...(ii) Now,                     ...(iii)                          ...(iv)                                                      ?(v)                 ?(vi)                                                                ?(vii) From Eq. (iii),                                    ...(viii) So, from Eqs. (vii) and (viii),  


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