question_answer

The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collision is     AIEEE  Solved  Paper-2005

A) \[\sqrt{MK}L\]                                                 

B) \[\frac{k{{L}^{2}}}{2M}\]  

C) zero      

D)        \[\frac{M{{L}^{2}}}{k}\]

Correct Answer: A

Solution :

Momentum would be maximum when KE would be maximum and this is the case when total elastic PE is converted into KE. According to conservation of energy, ( for spring)