A) the isobar of\[_{11}^{23}Na\]
B) the nuclide\[_{11}^{23}Na\]
C) the isobar of parent nucleus
D) the isotope of parent nucleus
Correct Answer: B
Solution :
\[_{12}^{24}Mg+\gamma \xrightarrow{{}}_{1}^{1}H+_{11}^{23}Na\] Thus, nuclide of \[_{11}^{23}Na\]is formed.
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