question_answer

A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be                    AIEEE  Solved  Paper-2003

A) 1 A                         

B) \[1.5\] A  

C)                       2 A                         

D) 1 A

Correct Answer: B

Solution :

Resistance in the arms AC and 6C are in series,                         \[\therefore \]                      \[R'=3+3=6\,\Omega \] Now, R' and \[3\,\Omega \] are in parallel. \[\therefore \]      \[{{R}_{eq}}=\frac{6\times 3}{6+3}=2\,\,\Omega \] Now,         \[V=lR\] \[\Rightarrow \]               \[l=\frac{3}{2}=1.5\,A\]