2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2003

  • question_answer
    The displacement y of a wave travelling in the x-direction is given by \[y={{10}^{-4}}\sin \left( 600\,t-2x+\frac{\pi }{3} \right)\] metre where, \[x\] is expressed in metres and t in seconds. The speed of the wave motion, in \[m{{s}^{-1}}\] is     AIEEE  Solved  Paper-2003

    A) 300     

    B)       600        

    C)       1200                      

    D)       200

    Correct Answer: A

    Solution :

                    If a wave equation is given, in order to determine the wave characteristics. We compare the given wave (or oscillation) with the general equation of wave. The given equation of wave \[y={{10}^{-4}}\sin \left( 600\,t-2x+\frac{\pi }{3} \right)\]  ... (i) Standard equation of wave \[y=a\sin \,\,(\omega t-kx+\phi )\]                              ... (ii) Now, comparing Eqs. (i) and (ii), we get                     \[\omega =600\] and k = 2  \[\therefore \] Velocity of wave \[=\frac{\omega }{k}=\frac{600}{2}=300\,m/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner