JEE Main & Advanced AIEEE Solved Paper-2003

  • question_answer
    A student is to answer 10 out of 13 questions in an examination such that he must choose atleast 4 from the first five questions. The number of choices available to him is     AIEEE  Solved  Paper-2003

    A) 140        

    B)       196        

    C)       280        

    D)       346

    Correct Answer: B

    Solution :

    The number of choices available to him     \[{{=}^{5}}{{C}_{4}}{{\times }^{8}}{{C}_{6}}{{+}^{5}}{{C}_{5}}{{\times }^{8}}{{C}_{5}}\]     \[=\frac{5!}{4!1!}\times \frac{8!}{6!2!}+\frac{5!}{5!0!}\times \frac{8!}{5!3!}\]     \[=5\times \frac{8\times 7}{2}\,+1\times \,\frac{8\times 7\times 6}{3\times 2}\]     \[=5\times 4\times 7+8\times 7\]     \[=140+56=196\]


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