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  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    In a transformer, number of turns in the primary are 140 and that in the secondary are 280. If current in primary is 4 A, then that in the secondary is AIEEE  Solved  Paper-2002

    A) 4 A            

    B)                           2 A  

    C)           6 A                            

    D)           10 A

    Correct Answer: B

    Solution :

                      Given \[{{i}_{p}}=4\,A\],  \[{{N}_{p}}=140\],           \[{{N}_{s}}=280\]              From the formula,                 \[\frac{{{i}_{p}}}{{{i}_{s}}}=\frac{{{N}_{s}}}{{{N}_{p}}}\]              or               \[\frac{4}{{{i}_{s}}}=\frac{280}{140}\]              So.           \[{{i}_{s}}=2\,A\]


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