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JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    Solubility of \[Ca{{(OH)}_{2}}\] is s \[mol{{L}^{-1}}\]. The solubility product \[({{K}_{sp}})\] under the same condition is   AIEEE  Solved  Paper-2002

    A) \[4{{s}^{3}}\]  

    B)                           \[3{{s}^{4}}\]                        

    C)           \[4{{s}^{2}}\]                        

    D)           \[{{s}^{3}}\]

    Correct Answer: A

    Solution :

    \[Ca{{(OH)}_{2}}\overset{{}}{leftrightarrows}C{{a}^{2+}}+2O{{H}^{-}}\] \[{{K}_{sp}}=[C{{a}^{2+}}]{{[O{{H}^{-}}]}^{2}}=(s){{(2s)}^{2}}=4{{s}^{3}}\]


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