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JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    Wavelength of light used in an optical instrument   are   \[{{\lambda }_{1}}=4000\,\overset{0}{\mathop{A}}\,\]   and \[{{\lambda }_{2}}=5000\,\overset{0}{\mathop{A}}\,\], then ratio of their respective resolving powers (corresponding to \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\]) is   AIEEE  Solved  Paper-2002

    A) \[16:25\]                

    B)           \[9:1\]                     

    C)           \[4:5\]   

    D)                           \[5:4\]

    Correct Answer: D

    Solution :

    Resolving power (RP) of an optical instrument is inversely proportional to \[\lambda \] i.e., RP \[\propto \frac{1}{\lambda }\].    \[\therefore \frac{\text{Resolving power at}\,{{\lambda }_{1}}}{\text{Resolving power at}\,{{\lambda }_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{5000}{4000}=5:4\]


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