A) \[a{{x}_{1}}+b{{y}_{1}}+c{{z}_{1}}=0\]
B) \[al+bm+cn=0\]
C) \[\frac{a}{l}=\frac{b}{m}=\frac{c}{n}\]
D) \[l\,{{x}_{1}}+m{{y}_{1}}+n{{z}_{1}}=0\]
Correct Answer: B
Solution :
The equation of plane containing the line \[\frac{x-{{x}_{1}}}{l}=\frac{y-{{y}_{1}}}{m}=\frac{z-{{z}_{1}}}{n}\]is \[a(x-{{x}_{1}})+b(y-{{y}_{1}})+c(z-{{z}_{1}})=0\], if \[al+bm+cn=0\] Since, the normal to the plane is perpendicular to the given line. \[\therefore \] \[al+bm+cn=0\]
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