A) twice that of 70 g N
B) half that of 20 g H
C) Both (a) and (b)
D) None of these
Correct Answer: C
Solution :
560 g of Fe Number of moles \[=\frac{560\,g}{56\,g}\,=10\,\] mole of Fe 14 g = 1 mole of N 70 g = 5 moles of N 20 g \[H\equiv 20\] moles of H-atoms
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