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JEE Main & Advanced AIEEE Paper (Held On 11 May 2011)

  • question_answer
    A 5% solution of cane sugar (molar mass 342) is isotonic with 1% of a solution of an unknown solute. The molar mass of unknown solute in g/mol is:     AIEEE  Solved  Paper (Held On 11 May  2011)

    A)  171.2             

    B)  68.4              

    C)  34.2

    D)  136.2

    Correct Answer: B

    Solution :

                                    \[{{\pi }_{1}}={{\pi }_{2}}\]                 \[{{C}_{1}}={{C}_{2}}\]                 \[\frac{5/342}{0.1}=\frac{1/M}{0.1}\]                 \[\frac{5}{342}=\frac{1}{M}\]\[\Rightarrow \]\[M=\frac{342}{5}=68.4gm/mol\]


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