A) \[2:1\]
B) \[\sqrt{2}:1\]
C) \[4:1\]
D) \[3:2\]
Correct Answer: A
Solution :
\[\Delta {{x}_{1}}=0\] \[\Delta \phi ={{0}^{o}}\] \[{{I}_{1}}={{I}_{0}}+{{I}_{0}}+2{{I}_{0}}\cos {{0}^{o}}=4{{I}_{0}}\] \[\Delta {{x}_{2}}=\frac{\lambda }{4}\] \[\Delta \theta =\frac{2\pi }{\lambda }.\frac{\lambda }{4}=\left( \frac{\pi }{2} \right)\] \[{{I}_{2}}={{I}_{0}}+{{I}_{0}}+2{{I}_{0}}\cos \frac{\pi }{2}=2{{I}_{0}}\] \[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{4{{I}_{0}}}{2{{I}_{0}}}=\frac{2}{1}.\]You need to login to perform this action.
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