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JEE Main & Advanced AIEEE Paper (Held On 11 May 2011)

  • question_answer
    At time t = 0 s a particle starts moving along the x-axis. If its kinetic energy increases uniformly with time 't', the net force acting on it must be proportional to:     AIEEE  Solved  Paper (Held On 11 May  2011)

    A)  constant           

    B)  t                   

    C) \[\frac{1}{\sqrt{t}}\]

    D) \[\sqrt{t}\]

    Correct Answer: C

    Solution :

                                    K.E. = ct \[\frac{1}{2}m{{v}^{2}}=ct\] \[\frac{{{P}^{2}}}{2m}=ct\] \[P=\sqrt{2ctm}\] \[F=\frac{dP}{dt}=\sqrt{2cm}\frac{1}{2}\times \frac{1}{\sqrt{t}}\] \[F\propto \frac{1}{\sqrt{t}}.\]


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