A) sulphur trioxide
B) sulphur dioxide
C) sulphur
D) a mixture of sulphur dioxide and sulphur trioxide
Correct Answer: A
Solution :
When cone. \[{{H}_{\,}}_{2}S{{O}_{4}}\]is heated with \[{{P}_{2}}{{O}_{s}},\]the acid is converted into sulphur trioxide. \[2{{H}_{2}}S{{O}_{4}}+2{{P}_{2}}{{O}_{5}}\xrightarrow[{}]{{}}\underset{\text{sulphur}\,\text{trioxide}}{\mathop{2S{{O}_{3}}}}\,+4HP{{O}_{3}}\]
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