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AFMC AFMC Solved Paper-2011

  • question_answer
    What is the equivalent weight of \[\text{SnC}{{\text{l}}_{\text{2}}}\]in the following reaction,\[\text{SnC}{{\text{l}}_{2}}\xrightarrow[{}]{{}}SnC{{l}_{4}}?\]

    A) 95                                          

    B) 45

    C) 60                                          

    D) 30

    Correct Answer: A

    Solution :

    Equivalent weight of  \[SnC{{l}_{2}}=\frac{mol.wt.}{2}=\frac{190}{2}\] = 95


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