A) elimination
B) polymerization
C) dimerisation
D) substitution
Correct Answer: A
Solution :
Haloalkanes on boiling with alcoholic \[\text{KOH}\]undergoes elimination or dehydrohalogenation. \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br+alc.KOH\xrightarrow[{}]{{}}\]\[\underset{propylene}{\mathop{C{{H}_{3}}CH=C{{H}_{2}}}}\,+KBr+{{H}_{2}}O\]
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