A) \[{{24}^{o}}44'\]
B) \[{{9}^{o}}44'\]
C) 44'
D) \[-{{5}^{o}}16'\]
Correct Answer: A
Solution :
\[\theta =\left[ 180-\frac{360}{n} \right]=\left[ 180-\frac{360}{3} \right]\] \[=180-120={{60}^{0}}\] Angle strain \[\alpha =\frac{1}{2}[{{190}^{o}}{{28}^{o}}-\theta ]\] \[=\frac{1}{2}[{{190}^{o}}{{28}^{o}}-{{60}^{o}}]={{24}^{o}}44'\] Thus, Angle strain in cyclopropane is \[{{24}^{o}}44'\]
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