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AFMC AFMC Solved Paper-2011

  • question_answer
    A convex lens is placed between object and a screen. The size of object is 3 cm and an image of height 9 cm is obtained on the screen. When the lens is displaced to a new position, what will be the size of image on the screen?

    A) 2 cm                                      

    B) 6 cm

    C) 4 cm                                      

    D) 1 cm

    Correct Answer: D

    Solution :

    From displacement method size of object, \[O=\sqrt{{{I}_{1}}{{I}_{2}}}\] Here, \[O=3\,cm,{{I}_{1}}=9\,cm\] \[\therefore \]       \[3=\sqrt{9{{I}_{2}}}\] or   \[{{I}_{2}}=1\,cm\]


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