A) \[2.5\times {{10}^{-6}}C\]
B) \[2\times {{10}^{-6}}C\]
C) \[{{10}^{-6}}C\]
D) \[8\times {{10}^{-6}}C\]
Correct Answer: A
Solution :
Given, \[B=0.5\,T\] \[{{A}_{1}}=101\,c{{m}^{2}}=101\times {{10}^{-4}}{{m}^{2}}\] \[{{A}_{2}}=100\,c{{m}^{2}}=100\times {{10}^{-4}}{{m}^{2}}\] \[R=2\Omega \] Amount of Charge \[q=\frac{B\Delta \Alpha }{R}\] \[=\frac{0.05\times (101\times {{10}^{-4}}-100\times {{10}^{-4}})}{2}\] \[=\frac{0.05\times 1\times {{10}^{-4}}}{2}=2.5\times {{10}^{-6}}C\]
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