A) 530 cal/g
B) 540 cal/g
C) 550 cal/g
D) 560 cal/g
Correct Answer: C
Solution :
Heat given for raising the temperature of W gram of water from \[0{{\,}^{o}}C\]to \[100{{\,}^{o}}C\]\[=W\times 1\times 100\] Time taken \[=10\times 60\,s\] \[\therefore \] Heat given per second \[=\frac{W\times 1\times 100}{10\times 60}cal\] Heat given out to convert W gram to steam \[=W\times L\] This is the heat supplied in \[55\times 60\,s.\] \[\therefore \] Heat given \[=100\times W\times \frac{55\times 60}{10\times 60}=WL\] \[\therefore \] \[L=\frac{100\times 55\times 60}{10\times 60}=100\times 5.5\] \[L=550\,cal/g\]
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