AFMC AFMC Solved Paper-2011

  • question_answer
    What is the refractive index of a prism whose angle \[A=60{}^\circ \] and angle of minimum deviation \[dm=30{}^\circ \] ?

    A) \[\sqrt{2}\]                                        

    B) \[\frac{1}{\sqrt{2}}\]

    C) 1                                             

    D) \[\frac{1}{\sqrt{3}}\]  

    Correct Answer: A

    Solution :

    Refractive index of prism \[\mu =\frac{\sin \frac{A+\delta m}{2}}{\sin A/2}=\frac{\sin \frac{{{60}^{o}}+{{30}^{o}}}{2}}{\sin \frac{{{60}^{o}}}{2}}\] \[=\frac{\sin {{45}^{o}}}{\sin {{30}^{o}}}=\frac{1/\sqrt{2}}{1/2}=\frac{1}{\sqrt{2}}\times \frac{2}{1}=\sqrt{2}\]


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