AFMC AFMC Solved Paper-2011

  • question_answer
    If 1 mg of U235 is completely annihilated, the energy liberated is

    A) \[9\times {{10}^{10}}J\]                                               

    B) \[9\times {{10}^{19}}J\]

    C) \[9\times {{10}^{18}}J\]                               

    D)  \[9\times {{10}^{17}}J\]

    Correct Answer: A

    Solution :

    \[E=m{{c}^{2}}\]                 \[E=({{10}^{-6}})\times (9\times {{10}^{16}})=9\times {{10}^{10}}\text{J}\]


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