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AFMC AFMC Solved Paper-2011

  • question_answer
    How many\[\frac{1}{6}\], s together make \[41\frac{2}{3}\]?

    A)  125                                       

    B)  150       

    C)   250      

    D)  350

    Correct Answer: C

    Solution :

                     \[\frac{41\frac{2}{3}}{\frac{1}{6}}=\frac{\frac{125}{3}}{\frac{1}{6}}=125\times \frac{6}{3}=250\]                


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